a(n)=(# 2's)-(# 3's) in first n terms of A031235.

Terms

a(0) =0a(1) =1a(2) =0a(3) =0a(4) =0a(5) =0a(6) =0a(7) =0a(8) =1a(9) =1a(10) =0a(11) =0a(12) =0a(13) =0a(14) =0a(15) =1a(16) =1a(17) =2a(18) =3a(19) =4a(20) =3a(21) =4a(22) =4a(23) =5a(24) =5a(25) =4a(26) =4a(27) =3a(28) =4a(29) =3