a(n)=(# 1's)-(# 0's) in first n terms of A030567.

Terms

a(0) =1a(1) =1a(2) =1a(3) =1a(4) =1a(5) =0a(6) =1a(7) =2a(8) =3a(9) =3a(10) =4a(11) =4a(12) =5a(13) =5a(14) =6a(15) =6a(16) =7a(17) =6a(18) =6a(19) =7a(20) =7a(21) =7a(22) =7a(23) =7a(24) =7a(25) =7a(26) =7a(27) =7a(28) =7a(29) =6