a(n)=(# 1's)-(# 0's) in first n terms of A030413.

Terms

a(0) =1a(1) =1a(2) =1a(3) =2a(4) =3a(5) =3a(6) =2a(7) =2a(8) =3a(9) =4a(10) =5a(11) =6a(12) =6a(13) =5a(14) =5a(15) =5a(16) =6a(17) =6a(18) =7a(19) =8a(20) =8a(21) =9a(22) =9a(23) =10a(24) =9a(25) =8a(26) =8a(27) =8a(28) =8a(29) =9