a(n)=(# 1's)-(# 0's) in first n terms of A030401.

Terms

a(0) =1a(1) =1a(2) =2a(3) =3a(4) =4a(5) =4a(6) =4a(7) =5a(8) =5a(9) =5a(10) =5a(11) =6a(12) =6a(13) =6a(14) =7a(15) =6a(16) =7a(17) =8a(18) =7a(19) =7a(20) =8a(21) =9a(22) =10a(23) =11a(24) =12a(25) =12a(26) =13a(27) =13a(28) =14a(29) =15