a(n)=(# 2's)-(# 3's) in first n terms of A030386.

Terms

a(0) =0a(1) =1a(2) =0a(3) =0a(4) =0a(5) =0a(6) =0a(7) =1a(8) =1a(9) =0a(10) =0a(11) =0a(12) =1a(13) =1a(14) =2a(15) =3a(16) =4a(17) =3a(18) =4a(19) =4a(20) =3a(21) =3a(22) =2a(23) =3a(24) =2a(25) =1a(26) =0a(27) =0a(28) =0a(29) =0