a(n)=(# 1's)-(# 2's) in first n terms of A030386.

Terms

a(0) =1a(1) =0a(2) =0a(3) =0a(4) =1a(5) =2a(6) =3a(7) =2a(8) =3a(9) =3a(10) =4a(11) =4a(12) =3a(13) =4a(14) =3a(15) =2a(16) =1a(17) =1a(18) =0a(19) =0a(20) =0a(21) =1a(22) =1a(23) =0a(24) =0a(25) =0a(26) =0a(27) =0a(28) =0a(29) =1