a(n)=(# 1's)-(# 0's) in first n terms of A030386.

Terms

a(0) =1a(1) =1a(2) =1a(3) =0a(4) =1a(5) =2a(6) =3a(7) =3a(8) =4a(9) =4a(10) =5a(11) =4a(12) =4a(13) =5a(14) =5a(15) =5a(16) =5a(17) =5a(18) =5a(19) =4a(20) =4a(21) =5a(22) =5a(23) =5a(24) =5a(25) =5a(26) =5a(27) =4a(28) =3a(29) =4