a(n)=(# 1's)-(# 0's) in first n terms of A030363.

Terms

a(0) =1a(1) =1a(2) =2a(3) =1a(4) =2a(5) =2a(6) =2a(7) =2a(8) =3a(9) =4a(10) =5a(11) =5a(12) =6a(13) =5a(14) =6a(15) =5a(16) =5a(17) =6a(18) =6a(19) =5a(20) =4a(21) =5a(22) =6a(23) =5a(24) =4a(25) =4a(26) =4a(27) =5a(28) =5a(29) =6