a(n) = (# 1's) - (# 2's) in first n terms of A030353.

Terms

a(0) =1a(1) =2a(2) =2a(3) =3a(4) =2a(5) =1a(6) =2a(7) =3a(8) =3a(9) =3a(10) =4a(11) =4a(12) =3a(13) =4a(14) =5a(15) =6a(16) =7a(17) =6a(18) =6a(19) =7a(20) =6a(21) =5a(22) =4a(23) =4a(24) =5a(25) =4a(26) =5a(27) =5a(28) =4a(29) =5