For n >= 2, let h=floor((n-1)/2), L=n-h, R=n+h; then a(L)=n if a(L) not yet defined, otherwise a(R)=n; thus |a(n)-n| = floor((1/2)*(a(n)-1)).

A026166

For n >= 2, let h=floor((n-1)/2), L=n-h, R=n+h; then a(L)=n if a(L) not yet defined, otherwise a(R)=n; thus |a(n)-n| = floor((1/2)*(a(n)-1)).

Terms

    a(0) =1a(1) =2a(2) =4a(3) =3a(4) =8a(5) =10a(6) =5a(7) =6a(8) =16a(9) =7a(10) =20a(11) =22a(12) =9a(13) =26a(14) =28a(15) =11a(16) =12a(17) =34a(18) =13a(19) =14a(20) =40a(21) =15a(22) =44a(23) =46a(24) =17a(25) =18a(26) =52a(27) =19a(28) =56a(29) =58

External references