s(1)s(n) + s(2)s(n-1) + ... + s(k)s(n+1-k), where k = [ (n+1)/2 ], s = A014306.

Terms

a(0) =0a(1) =0a(2) =1a(3) =1a(4) =1a(5) =1a(6) =2a(7) =2a(8) =3a(9) =3a(10) =3a(11) =3a(12) =5a(13) =4a(14) =5a(15) =5a(16) =6a(17) =6a(18) =7a(19) =7a(20) =7a(21) =7a(22) =9a(23) =8a(24) =9a(25) =9a(26) =10a(27) =10a(28) =12a(29) =11