a(n) = s(1)t(n) + s(2)t(n-1) + ... + s(k)t(n+1-k), where k = [ (n+1)/2 ], s = A023532, t = A014306.

Terms

a(0) =0a(1) =1a(2) =1a(3) =0a(4) =2a(5) =1a(6) =2a(7) =3a(8) =3a(9) =2a(10) =4a(11) =3a(12) =4a(13) =5a(14) =5a(15) =5a(16) =5a(17) =6a(18) =6a(19) =6a(20) =8a(21) =7a(22) =8a(23) =9a(24) =9a(25) =9a(26) =9a(27) =10a(28) =10a(29) =10