a(n) = ((n+2)!/2)(1/3 - 1/4 + ... + c/(n+2)), where c = (-1)^(n+1).

A024188

a(n) = ((n+2)!/2)(1/3 - 1/4 + ... + c/(n+2)), where c = (-1)^(n+1).

Terms

    a(0) =1a(1) =1a(2) =17a(3) =42a(4) =654a(5) =2712a(6) =44568a(7) =264240a(8) =4721040a(9) =36694080a(10) =716523840a(11) =6917823360a(12) =147356496000

External references