a(n) = a(n-1) + c(n-1) for n >= 2, a( ) increasing, given a(1)=3, where c( ) is complement of a( ).

Terms

a(0) =3a(1) =4a(2) =6a(3) =11a(4) =18a(5) =26a(6) =35a(7) =45a(8) =57a(9) =70a(10) =84a(11) =99a(12) =115a(13) =132a(14) =151a(15) =171a(16) =192a(17) =214a(18) =237a(19) =261a(20) =286a(21) =313a(22) =341a(23) =370a(24) =400a(25) =431a(26) =463a(27) =496a(28) =530a(29) =566