From George Gilbert's marks problem: jumping 7 marks at a time (final positions).

Terms

a(0) =2a(1) =4a(2) =7a(3) =14a(4) =87a(5) =110a(6) =178a(7) =1551a(8) =2311a(9) =2820a(10) =2862a(11) =5158a(12) =9267a(13) =15867a(14) =25023a(15) =34363a(16) =68486a(17) =2570490a(18) =4313372a(19) =21511363a(20) =22412883a(21) =54933234a(22) =66947210a(23) =341535842a(24) =995434171a(25) =1491645143a(26) =4258696422a(27) =26212684635a(28) =28500533228