a(n) = (F(n+1)+L(n)+n)^2 where F(n) are the Fibonacci numbers (A000045) and L(n) are the Lucas numbers (A000032).
A014718
a(n) = (F(n+1)+L(n)+n)^2 where F(n) are the Fibonacci numbers (A000045) and L(n) are the Lucas numbers (A000032).
Terms
- a(0) =9a(1) =9a(2) =49a(3) =100a(4) =256a(5) =576a(6) =1369a(7) =3249a(8) =7921a(9) =19600a(10) =49284a(11) =125316a(12) =321489a(13) =829921a(14) =2152089a(15) =5597956a(16) =14592400a(17) =38093584a(18) =99540529a(19) =260273689a(20) =680844649a(21) =1781515264a(22) =4662431524a(23) =12203620900a(24) =31944770361a(25) =83624494041a(26) =218918244769a(27) =573112589764
External references
- oeis: A014718