a(n+1) = a(n) + sum of digits in base 3 representation of a(n), with a(0) = 1.

Terms

a(0) =1a(1) =2a(2) =4a(3) =6a(4) =8a(5) =12a(6) =14a(7) =18a(8) =20a(9) =24a(10) =28a(11) =30a(12) =32a(13) =36a(14) =38a(15) =42a(16) =46a(17) =50a(18) =56a(19) =60a(20) =64a(21) =68a(22) =74a(23) =80a(24) =88a(25) =92a(26) =96a(27) =100a(28) =104a(29) =110