Let j = | i - i_written_backwards |, k = j + j_written_backwards; then k is in this sequence.

Terms

a(0) =0a(1) =18a(2) =99a(3) =198a(4) =261a(5) =342a(6) =423a(7) =504a(8) =585a(9) =666a(10) =747a(11) =828a(12) =909a(13) =1089a(14) =1170a(15) =1251a(16) =1332a(17) =1413a(18) =1494a(19) =1575a(20) =1656a(21) =1737a(22) =1818a(23) =1881a(24) =1998a(25) =2772a(26) =2871a(27) =3663a(28) =3762a(29) =4554