Let P(n) of a sequence s(1),s(2),s(3),... be obtained by leaving s(1),...,s(n) fixed and reversing every n consecutive terms thereafter; apply P(2) to 1,2,3,... to get PS(2), then apply P(3) to PS(2) to get PS(3), then apply P(4) to PS(3), etc. This sequence is the limit of PS(n).

A007062

Let P(n) of a sequence s(1),s(2),s(3),... be obtained by leaving s(1),...,s(n) fixed and reversing every n consecutive terms thereafter; apply P(2) to 1,2,3,... to get PS(2), then apply P(3) to PS(2) to get PS(3), then apply P(4) to PS(3), etc. This sequence is the limit of PS(n).

Terms

    a(0) =1a(1) =2a(2) =4a(3) =5a(4) =7a(5) =12a(6) =14a(7) =15a(8) =23a(9) =28a(10) =30a(11) =41a(12) =43a(13) =48a(14) =56a(15) =67a(16) =69a(17) =84a(18) =86a(19) =87a(20) =111a(21) =116a(22) =124a(23) =139a(24) =141a(25) =162a(26) =180a(27) =181a(28) =183a(29) =224

External references