Let P(n) of a sequence s(1),s(2),s(3),... be obtained by leaving s(1),...,s(n) fixed and reversing every n consecutive terms thereafter; apply P(2) to 1,2,3,... to get PS(2), then apply P(3) to PS(2) to get PS(3), then apply P(4) to PS(3), etc. This sequence is the limit of PS(n).
A007062
Let P(n) of a sequence s(1),s(2),s(3),... be obtained by leaving s(1),...,s(n) fixed and reversing every n consecutive terms thereafter; apply P(2) to 1,2,3,... to get PS(2), then apply P(3) to PS(2) to get PS(3), then apply P(4) to PS(3), etc. This sequence is the limit of PS(n).
Terms
- a(0) =1a(1) =2a(2) =4a(3) =5a(4) =7a(5) =12a(6) =14a(7) =15a(8) =23a(9) =28a(10) =30a(11) =41a(12) =43a(13) =48a(14) =56a(15) =67a(16) =69a(17) =84a(18) =86a(19) =87a(20) =111a(21) =116a(22) =124a(23) =139a(24) =141a(25) =162a(26) =180a(27) =181a(28) =183a(29) =224
External references
- oeis: A007062