Continued fraction for 4^5*Sum_{n>=0} 1/4^(2^n).

Terms

a(0) =324a(1) =63a(2) =1a(3) =1023a(4) =64a(5) =1023a(6) =1a(7) =63a(8) =1023a(9) =1a(10) =63a(11) =1023a(12) =1a(13) =62a(14) =1a(15) =1023a(16) =63a(17) =1a(18) =1023a(19) =64a(20) =1023a(21) =1a(22) =63a(23) =1023a(24) =1a(25) =62a(26) =1a(27) =1023a(28) =64a(29) =1023