Continued fraction for Sum_{n>=0} 1/4^(2^n).

Terms

a(0) =0a(1) =3a(2) =6a(3) =4a(4) =4a(5) =2a(6) =4a(7) =6a(8) =4a(9) =2a(10) =6a(11) =4a(12) =2a(13) =4a(14) =4a(15) =6a(16) =4a(17) =2a(18) =6a(19) =4a(20) =4a(21) =2a(22) =4a(23) =6a(24) =2a(25) =4a(26) =6a(27) =4a(28) =2a(29) =4