Number of points on surface of truncated tetrahedron: a(n) = 14*n^2 + 2 for n > 0, a(0)=1.

A005905

Number of points on surface of truncated tetrahedron: a(n) = 14*n^2 + 2 for n > 0, a(0)=1.

Terms

    a(0) =1a(1) =16a(2) =58a(3) =128a(4) =226a(5) =352a(6) =506a(7) =688a(8) =898a(9) =1136a(10) =1402a(11) =1696a(12) =2018a(13) =2368a(14) =2746a(15) =3152a(16) =3586a(17) =4048a(18) =4538a(19) =5056a(20) =5602a(21) =6176a(22) =6778a(23) =7408a(24) =8066a(25) =8752a(26) =9466a(27) =10208a(28) =10978a(29) =11776

External references