Maximal number of pieces obtained by slicing a torus (or a bagel) with n cuts: (n^3 + 3*n^2 + 8*n)/6 (n > 0).
A003600
Maximal number of pieces obtained by slicing a torus (or a bagel) with n cuts: (n^3 + 3*n^2 + 8*n)/6 (n > 0).
Terms
- a(0) =1a(1) =2a(2) =6a(3) =13a(4) =24a(5) =40a(6) =62a(7) =91a(8) =128a(9) =174a(10) =230a(11) =297a(12) =376a(13) =468a(14) =574a(15) =695a(16) =832a(17) =986a(18) =1158a(19) =1349a(20) =1560a(21) =1792a(22) =2046a(23) =2323a(24) =2624a(25) =2950a(26) =3302a(27) =3681a(28) =4088a(29) =4524
External references
- oeis: A003600