a(n) = 4^floor(n/2)*a(n-1) - a(n-2), for n >= 2, with a(0) = a(1) = 1.
A003115
a(n) = 4^floor(n/2)*a(n-1) - a(n-2), for n >= 2, with a(0) = a(1) = 1.
Terms
- a(0) =1a(1) =1a(2) =3a(3) =11a(4) =173a(5) =2757a(6) =176275a(7) =11278843a(8) =2887207533a(9) =739113849605
External references
- oeis: A003115