For n > 1: a(n) = a(n-1)^3 + 3a(n-1)^2 - 3; a(0) = 1, a(1) = 2.

A002814

For n > 1: a(n) = a(n-1)^3 + 3a(n-1)^2 - 3; a(0) = 1, a(1) = 2.

Terms

    a(0) =1a(1) =2a(2) =17a(3) =5777a(4) =192900153617

External references