Primes p such that the congruence 2^x = 5 (mod p) is solvable.

Terms

a(0) =2a(1) =3a(2) =11a(3) =13a(4) =19a(5) =29a(6) =37a(7) =41a(8) =53a(9) =59a(10) =61a(11) =67a(12) =71a(13) =79a(14) =83a(15) =101a(16) =107a(17) =131a(18) =139a(19) =149a(20) =163a(21) =173a(22) =179a(23) =181a(24) =191a(25) =197a(26) =199a(27) =211a(28) =227a(29) =239