Primes p such that the congruence 2^x == 3 (mod p) is solvable.

Terms

a(0) =2a(1) =5a(2) =11a(3) =13a(4) =19a(5) =23a(6) =29a(7) =37a(8) =47a(9) =53a(10) =59a(11) =61a(12) =67a(13) =71a(14) =83a(15) =97a(16) =101a(17) =107a(18) =131a(19) =139a(20) =149a(21) =163a(22) =167a(23) =173a(24) =179a(25) =181a(26) =191a(27) =193a(28) =197a(29) =211