a(n)-th triangular number is a square: a(n+1) = 6*a(n) - a(n-1) + 2, with a(0) = 0, a(1) = 1.
A001108
a(n)-th triangular number is a square: a(n+1) = 6*a(n) - a(n-1) + 2, with a(0) = 0, a(1) = 1.
Terms
- a(0) =0a(1) =1a(2) =8a(3) =49a(4) =288a(5) =1681a(6) =9800a(7) =57121a(8) =332928a(9) =1940449a(10) =11309768a(11) =65918161a(12) =384199200a(13) =2239277041a(14) =13051463048a(15) =76069501249a(16) =443365544448
External references
- oeis: A001108