941432800

Appears in sequences

• Let b(0)=0. For n >= 1, b(n) is the least k > b(n-1)+1 such that k divides (k-1)!/b(n-1)!, and a(n) = (b(n)-1)!/(b(n-1)!*b(n)).at n=5A079759
• Duplicate of A079759.at n=5A109894
• a(n) = A332560(n)/A332559(n).at n=28A332561