8920484118domain: NAppears in sequencesNumerators of continued fraction convergents to sqrt(277).at n=20A041520Let p(n) be the n-th prime congruent to 1 mod 4. Then a(n) = the least m for which m^2+1=p(n)*k^2 has a solution.at n=26A094048Value x in the solution of x^2-D*y^2=-1 as D runs through A003654.at n=45A249021