88737domain: NAppears in sequencesa(n) = floor(2^n*log(n)).at n=14A094939Number of walks within N^3 (the first octant of Z^3) starting at (0,0,0) and consisting of n steps taken from {(-1, -1, 1), (0, 0, 1), (0, 1, 0), (1, 1, -1), (1, 1, 0)}.at n=8A151128a(n) = Sum_{k=0..floor(n/2)} binomial(n-k,k)^n * n/(n-k).at n=5A181083