879899

Appears in sequences

• Start to read the sequence digit by digit and erase the first "1" you encounter, then the first "2", the first "3", etc., until the first "9"; go on from there and erase again the first "1", the first "2", etc., until "9" -- and so on, cyclically until the end of the (infinite) sequence. Concatenate what is left. The result is the concatenation of all integers of the sequence.at n=17A108709
• Numbers that have the largest possible remainder when divided by their digit sum.at n=26A348799