873813

Appears in sequences

• a(n) = a(n-1) + 2*a(n-2), a(0)=2, a(1)=3.at n=19A048573
• a(n+1) = smallest number not containing any digits of a(n), working in base 4.at n=23A049548
• Multiples of 3 which on one operation of the Collatz function T (N -> 3N+1/2^r) yield the number 5.at n=3A072196
• a(n) = 4*a(n-1) + 1 with a(0) = 3.at n=9A072197
• Numbers n for which one step of the Collatz iteration (3n+1)/2^r gives rise to values 59,53,47,41,35,29,23,17,11 and 5 for r=1,3,5,..,19.at n=9A072253
• Numbers k such that A081252(m)/m^2 has a local maximum for m = k.at n=19A081254
• a(n) is the index of F(n+1) at the unique occurrence of the ordered pair of reversed consecutive terms (F(n+1),F(n)) in Stern's diatomic sequence A002487, where F(k) denotes the k-th term of the Fibonacci sequence A000045.at n=19A086893
• a(n) = 4*a(n-2) + 1 with a(1) = 0, a(2) = 3.at n=19A096773
• A generalized Jacobsthal sequence.at n=18A159290
• Locations of row maxima in "crushed" version of Stern's diatomic array.at n=37A169969
• Odd numbers producing exactly 3 odd numbers in the Collatz (3x+1) iteration.at n=30A198584
• Least n such that L(n)<-1 and L(n)<L(n-1), where L(k) means the least root of the polynomial p(k,x) defined at A206284, and a(1)=13.at n=8A206444
• Odd numbers producing 3 decreasing odd numbers in the Collatz (3x+1) iteration.at n=27A228872
• a(n) = 4*a(n-2)+1 with initial terms 1,3,7.at n=19A283323
• Numbers of the form (2^(2*j + 6*k + 5) - 2^(2*j + 1) - 3)/9, with j,k >= 0.at n=18A342815
• Array A read by upward antidiagonals in which the entry A(n,k) in row n and column k is defined by A(n, k) = 4^n*(6*k - 3 - 2*(-1)^n) + (4^n - 1)/3, n,k >= 1.at n=47A371100
• Array A read by upward antidiagonals in which the entry A(n,k) in row n and column k is defined by A(1, k) = 4*k-1, and A(n+1, k) = A371094(A(n, k)), n,k >= 1.at n=11A371102
• Array A read by upward antidiagonals in which the entry A(n,k) in row n and column k is defined by A(1, k) = 4*k-1, and A(n+1, k) = A371094(A(n, k)), n,k >= 1.at n=24A371102
• Array read by upward antidiagonals: A(n, k) = A371094(A(n-1, k)) for n > 1, k >= 1; A(1, k) = 2*k-1.at n=24A372282