82793

Properties

Appears in sequences

• Third term of balanced prime quartets: p(m-1)-p(m-2) = p(m)-p(m-1) = p(m+1)-p(m).at n=30A054802
• a(n) = 4*a(n-1) - 2*a(n-2) + a(n-3) - 4*a(n-4) + a(n-5) for n >= 6, where a(1) = 1, a(2) = 3, a(3) = 5, a(4) = 16, a(5) = 53.at n=10A339828
• Prime numbersat n=8092