82372752domain: NAppears in sequencesa(n) = 28*(n+1)*binomial(n+6,8)/3.at n=15A027820a(n) = A081537(n)/A081535(n), with a(2) = 1 by convention.at n=24A081538a(n) = 42*binomial(n,10).at n=24A088626a(n) = floor(lcm(1,2,...n)/(1+2+...+n)).at n=24A109922