817138163595domain: NAppears in sequencesa(n) = Lucas(4n+1) - 1, or 5*Fibonacci(2n)*Fibonacci(2n+1).at n=14A081017a(n) = Lucas(3*n) - 1.at n=19A100233Continued fraction expansion for exp( Sum_{n>=1} 1/(n*A014448(n)) ), where A014448(n) = (2+sqrt(5))^n + (2-sqrt(5))^n.at n=28A174506