77998domain: NAppears in sequencesa(n) = floor( (2/(exp(1) - 2))^n ) for n >= 2, a(1) = 1.at n=10A088656a(n) = 5^n - 2^n + 1^n.at n=7A155596Square array T(n,k), n >= 1, k >= 1, read by antidiagonals downwards, where T(n,k) = Sum_{j=1..n} (-1)^(j+1) * floor(n/j)^k.at n=59A344726