68494domain: NAppears in sequencesa(n) = (2*n-1)*(5*n^2-5*n+6)/6.at n=34A063489Numbers k such that the sum of the digits of k^sigma(k) is divisible by k.at n=23A109658a(n) = n * Fibonacci(n) - Sum_{i=0..n} Fibonacci(i).at n=19A122491