68276domain: NAppears in sequencesNumber of divisors of 240^n.at n=25A103532a(n) = n^3 + reversal of digits of n^3.at n=25A319603a(n) = n^2 * prime(n).at n=25A356868a(n) = n + 2*binomial(n,2) + 3*binomial(n,3) + 4*binomial(n,4).at n=26A361099