68174domain: NAppears in sequencesIntersection of A108027, A108028, A108029 and A108030.at n=26A108109G.f. A(x) satisfies: A(x) = B(x)^2 + C(x)^2 such that B(x) + I*C(x) = Series_Reversion(x - I*A(x)), where I^2 = -1.at n=4A263530G.f. satisfies A(x) = 1 + x * A(x)^(1/2) * (1 + A(x)^(5/2)).at n=7A370471