66666665

Appears in sequences

• Numbers k such that k^2 contains only digits {2,4,5}.at n=25A031154
• a(0) = 0; a(n) is obtained by incrementing each digit of a(n-1) by 5.at n=7A061518
• Numbers k such that k and k^2 use only the digits 2, 4, 5 and 6.at n=11A137093
• For k in {2,3,...,9} define a sequence as follows: a(0)=0; for n>=0, a(n+1)=a(n)+1, unless a(n) ends in k, in which case a(n+1) is obtained by replacing the last digit of a(n) with the digit(s) of k^2. This is k(8).at n=40A237345
• Numbers k such that k+2 divides concat(k, k+1).at n=9A281232