6643838878domain: NAppears in sequencesa(n) = Lucas(4n+3) - 1, or Lucas(2n+1)*Lucas(2n+2).at n=11A081019Row sums of triangle defined in A096539.at n=14A160909a(n) = L(n)*L(n+1), where L = A000032 (Lucas numbers).at n=23A215602