66163

Appears in sequences

• Numbers k such that the period of the continued fraction for sqrt(k) contains exactly 65 ones.at n=2A031833
• Divide the natural numbers in sets of consecutive numbers starting with {1,2} as the first set. The number of elements of the n-th set is equal to the sum of the n-1 final numbers in the (n-1)st set. The final number of the n-th set gives a(n).at n=7A067353
• Let f(p,i) = smallest prime m >= p such that m == i (mod p); a(n) = Sum_{i=0..p-1} f(p,i), where p = n-th prime.at n=28A243076