65722domain: NAppears in sequencesa(n) = [ a(n-1)/a(1) ] + [ a(n-1)/a(2) ] + ... + [ a(n-1)/a(n-1) ] for n >= 3, with initial terms 2,2.at n=16A022868a(n) = A070952(2^n).at n=16A246023a(n) = n^3 + (n+1)*(n+2).at n=40A270109