56883domain: NAppears in sequencesNumbers k such that k^12 == 1 (mod 13^4).at n=22A056095Put a [+] b = A(A(a) + A(b)), where A=A007913. The sequence lists consecutive row "sums" of triangle A248473, using [+].at n=23A249388a(n) = 2*a(n-1) - a(n-2) + a([n/2]), where a(0) = 1, a(1) = 1, a(2) = 1.at n=39A298414