536870916domain: NAppears in sequencesa(n) = 2^n + 4.at n=29A140504a(0) = 4; for n >= 1, a(n) = 2^n + 4.at n=29A146528a(n) = n*(n^9+1)/2.at n=8A168118p-INVERT of (1,1,1,1,1,...), where p(S) = (1 - S^3)^2.at n=28A291014