48956domain: NAppears in sequencesThe number of primes of the form i^2 + j^4 (A028916) <= 2^n.at n=25A226498Numbers k such that phi(k) is a Lucas number.at n=19A373194G.f. satisfies A(x) = A(x^2) + A(x^2)^2*A(x^3)/A(x^6), with A(0) = 0 and A'(0) = 1.at n=46A382316