481615domain: NAppears in sequencesa(1) = 1; a(n+1) = sum of terms in continued fraction for sum of continued fractions, [a(n); a(n-1), a(n-2),...,a(1)] and [0; a(n), a(n-1), a(n-2),...,a(1)].at n=23A058083Numbers n such that the average of prime(n) and prime(n+1) is a perfect cube.at n=27A076693