481579499520domain: NAppears in sequencesa(1) = 1, a(n) = smallest multiple of n divisible by the sum of all previous terms.at n=20A074179a(n) = A092287(n)/A129364(n).at n=23A129365a(1)=1; for n>1, a(n) = a(n-1) + lcm(a(n-1),n).at n=19A135504