4807526973domain: NAppears in sequencesa(n) = Fibonacci(4n)-3, or Fibonacci(2n-2)*Lucas(2n+2).at n=11A081074a(n) = L(n)*L(n+1) mod F(n+2) where F=A000045 is the Fibonacci numbers and L = A000032 is the Lucas numbers.at n=46A348591